1. 总结
1）下面两种方式的字符串赋值均正确
char str1[] = "hello str1";
char *str2 = "hello str2";
char *str3; str3 = "hello str3";
2）char str1[] = "hello str1"; 是将字符串赋值给数组，字符串存在数组里（这里是栈），可以修改字符串内容，可读可写。
3） char *str2 = "hello str2"; 是将字符串地址赋值给指针变量，字符串本身存在只读内存区，不可通过指针对其进行修改，只读不可写。
4）str3 = "hello str3"; 同3）
2. 代码：
#include
#include
void main(void)
{
char str1[] = "hello str1";
char *str2 = "hello str2";
//str1[0] = 'a';
//str2[0] = 'a';
printf("str1: %s\n", str1);
printf("str2: %s\n", str2);
}
3. 结果：
baoli@ubuntu:~/c$ ./a.out
str1: hello str1
str2: hello str2
将上述代码两行注释去掉，编译，运行：
baoli@ubuntu:~/c$ ./a.out
Segmentation fault (core dumped)
4. gdb调试：gdb ./a.out
(gdb) run
Starting program: /home/baoli/c/a.out
warning: the debug information found in "/lib64/ld-2.19.so" does not match "/lib64/ld-linux-x86-64.so.2" (CRC mismatch).
Program received signal SIGSEGV, Segmentation fault.
0x00000000004005dc in main () at test.c:11
11 str2[0] = 'a';
(gdb)
(gdb) print str2
$1 = 0x4006b4 "hello str2"
(gdb) print str1
$2 = "aello str1"